Compare the functions represented by the ordered pairs: set a: {(5,1), (4,4), (3,9), (2,16), (1,25)} set b: {(1,-5), (2,-3), (3,-1), (4,1), (5,3)}

We are given

Set A: {(5,1), (4,4), (3,9), (2,16), (1,25)}

We can see that for each x value of the set is increasing exponentially.

y=(6-5)^2 = (1)^2 = 1

y=(6-4)^2 = (2)^2 = 4

y=(6-3) = (3)^2 = 9

y=(6-2)^2 = (4)^2 = 16

y=(6-1)^2 = (5)^2 = 25.

For set B:

Set B: {(1,-5), (2,-3), (3,-1), (4,1), (5,3)}

It's simply linear function as diffrences of y values are constant that is 2.

y = 2(1) -7 = 2-7 = -5

y = 2(2) -7 = 4-7 = -3

y = 2(3) -7 = 6-7 = 1

y = 2(4) -7 = 8-7 = 1

y = 2(5) -7 = 10-7 = 3.

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled