Find the value of 2a^2+5b^2 when a=-6 and b=2

2(6)^2+5(2)^2

2*36+5(2)^2

2*36+5*4

72+5*4

72+20

=92

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

imma say 16%. sorry if its wrong. i'm doing the same stuff right now

step-by-step explanation: