so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre
so in quadrilateral oabc
< coa + < oab + < ocb + < abc = 360
150 +90+90 + < abc = 360
330 + < abc = 360
< abc = 360 -330 = 30
so < abc = 30
⭐dhruv⭐
Answer from: Quest
4x and 6y
im not sure though
Another question on Mathematics
Mathematics, 21.06.2019 16:00
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Which of these equations, when solved, gives a different value of x than the other three? a9.1 = -0.2x + 10 b10 = 9.1 + 0.2x c10 – 0.2x = 9.1 d9.1 – 10 = 0.2x