Find the zeros of the graph of f(x) = x^3 + x^2 - 4x - 4.

x= -2,   -1,   +2

Step-by-step explanation:

Hey there!

... x³ + x² - 4x - 4 = 0

... x² ( x + 1 ) - 4 ( x + 1 ) = 0

... ( x² - 4 ) ( x + 1 ) = 0

Note :- a²-b²=(a+b)(a-b)

... ( x + 2 ) ( x - 2 ) ( x + 1 ) = 0

Hence, the answers are :-

... -2,2,-1

Hope it helps!

the answer is c.

for continuous functions, they continue in the same pattern and you have to find that pattern kinda like slope