Given a line segment with end points a (0,0) and b (6,8), find point c (x, y) that the triangle vertices a, b and c has an area of 25 square units?

C(6.25 , 0)

Step-by-step explanation:

Draw the diagram

A is at (0,0)

B is at (6,8)

Draw a line from A to B.

Put a large dot where (0,6) is. Call this D

Draw BD

Draw another line from (0,0) to just beyond (6,0) Call this C. Draw in BC

What You Have Drawn

The height of the triangle is BD and it is 8. That comes from B which is (6,8)

Solve

Formula

Area = 1/2 * B * H

Area = 25

H = 8

Area = 1/2 B * H

25 = 1/2 * B * 8             Switch sides

1/2  * B * 8 = 25            Combine factors on the left.

4 B = 25                       Divide both sides by 4

4B/4  = 25/4        

B = 6.25

What that means is that AC is 6.25 units long and is on the x axis

C is C(6.25,0)

the answer is the third / last answer

step-by-step explanation:

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.