Identify all of the root(s) of g(x) = (x2 + 3x - 4)(x2 - 4x + 29). -1 1 -4 4 2 + 5i 2 - 5i -2 + 10i -2 - 10i

1, -4, 2 + 5i, 2 - 5i

Step-by-step explanation:

First, I factor x^2 + 3x - 4

==> I get: (x - 1) (x +4)

Then, I factor (x^2 - 4x + 29)

==> And I get (2 + 5i) (2 - 5i)

You can use the quadratic formula to factor or use the "X" to solve them.

Hope this help!

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

im here

step-by-step explanation: