, i need find the equation of a line that passes through the point (−2,5), and is parallel to the line y=−3x+4. a. y=−3x−10 b. y=−3x−1 c. y=−3x−3 d. y=−3x e. y=−3x+1

B.y=−3x−1

Step-by-step explanation:

given that the line is parallel to y = -3x+4

Hence required line will be of the form

y =-3x+k for some k.

(Reason: slopes will be equal for parallel lines)

Since the line passes through (-2,5)

Substitute x =-2 and y =5 in the equation.

5=-3(-2)+k

Simplify

5 = 6+k

Subtract 6

Or k =-1

Hence required line has equation y =-3x-1

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1