Describe the end behavior of the following function:

A ) The graph of the function start high and ends low .

Step-by-step explanation:

Given  : f(x) = .

To find : Describe the end behavior of the following function.

Solution : We have given function

f(x) = .

We can see the Degree = 5  ( Odd) ,  Leading coefficient = negative  .

By the End Behavior Rule  : If  the degree odd and leading coefficient is negative then the left side of graph would be up and right would be down.

Therefore, A ) The graph of the function start high and ends low .

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt