Aprojectile is launched upward with a velocity of 288 feet per second from the top of a 65 foot structure . what is the maximum height attained by the projectile ?

The maximum height attained by the projectile is 412.94 meters = 1359.79 feet.

Step-by-step explanation:

The height formula has the following formula:

In which is the initial height, is the initial speed and g = 9.8 m/s² is the gravity.

In this problem, we have that:

We are working with the gravity in meters, so we must convert the feet measures to meters.

Each feet has 0.3048 meters.

So 288 feet per second = 87.78 meters per second.

65 foot = 19.81 meters.

This means that:

So

The maximum height is attained at the moment of time in which the velocity is 0. The velocity is the derivative of the height. So:

The maximum height is attained at 8.96s. This height is

The maximum height attained by the projectile is 412.94 meters = 1359.79 feet.

the sum of all the angles in a triangle are equal to 180

so you can add   the 3 given angles together to equal 180:

5y + 2y + 2y = 180

or since all three angles have the same letter, combine the 3 angles to equal 180:

9y = 180

56

step-by-step explanation: