Find three consecutive even integers such that the sum of the smallest number and twice the middle number is 20 more than the largest number?

10,12,14

Step-by-step explanation:

Two consecutive integers will have difference of 2.

Let 3 consecutive even integers be a-2, a, a+2

Smallest number = a-2 and middle number = a

Sum of the smallest number and twice the middle number

= a-2+2a =3a-2

20 more than the largest number = 20+a+2 =a+22

i.e. 3a-2 = a+22

2a = 24

Or a =12

Hence three integers even consecutive are 12-2, 12, 12+2

=10,12,14

answer:   rlly

step-by-step explanation:

yes

step-by-step explanation: