Atriangular frame has sides that measure 15'-7",20'-4" and 26'-2". what is the total length of three sides?

we know that

Part 1)

we know that

side 1=15'-7"

side 2=20'-4"

side 3=26'-2"

To find the total length of three sides sum the three sides

so

total length=side 1+side 2 +side 3

substitute

total length=15'-7"+20'-4"+26'-2"

total length=(15'+20'+26')+(7"+4"+2")

total length=(61')+(13")

remember that

12"=1'

13"=12"+1"=1'+1"

substitute

total length=(61')+(1'+1")

total length=(62')+(1")---------> 62'-1"

therefore

the answer is

the total length of three sides is 62'-1"

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation: