The intercepts of y = − x^2+ b x + c y = - x 2 + b x + c are − 2 ± √ 17 - 2 ± 17 . which of the following are solutions of − x^2 + b x + c ≥ 0 - x 2 + b x + c ≥ 0 ?

Given a generic parabola

the parabola is concave up if and concave down if

Since in this case , the parabola is concave down, which means that it is positive between its solutions.

Since

all options between -6.12 and 2.12 will be fine.

So, the first three options fall inside this interval, and thus f(x)>0 for those points.

Instead, is greater than the greater solution, and so f(x)<0 for that point.

rectangle that is ther answer you

step-by-step explanation:

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify