Acompany did a quality check on all the packs of trail mix it manufactured. each pack of trail mix is targeted to weigh 9.25 oz. a pack must weigh within 0.23 oz of the target weight to be accepted. find the absolute value inequality that describes the situation and solve it to find the range of rejected masses, x. |x − 0.23| + 9.25 > 0; x < 9.02 or x > 9.48 |x − 9.25| > 0.23; x < 9.25 or x > 9.48 |x − 0.23| + 9.25 > 0; x < 9.25 or x > 9.48 |x − 9.25| > 0.23; x < 9.02 or x > 9.48

Each pack of trail mix is targeted to weigh 9.25 oz.

A pack must weigh within 0.23 oz of the target weight to be accepted.

Let the weight of the pack x

The range of accepted weight will be as following:

∴ 9.25 - 0.23 < x < 9.25 + 0.23  

subtract 9.25 from all sides

∴ -0.23 < x - 9.25 < 0.23

which can be written as ⇒⇒⇒  | x - 9.25 | < 0.23

So, the rejected weight is the inverse of that inequality.

∴ The absolute value inequality for the rejected weight range is:

| x - 9.25 | > 0.23

So, the range of rejected masses:    x < 9.02   OR  x > 9.48

the right system of equations to describe the situation would

be on the form:

x1 = 8000 + y1*t

and

x2 = 8000 + y2*t

where x1 and x2 represents the total money of imogene and her

friend respectively at the end of t years.

now for the value of amount earned, y1 and y2:

y1=8000*0.08

y2=2000*√(t-2)

step-by-step explanation: