At 6: 00 p. m. the temperature was -5*f outside. by midnight the temperature had dropped 12 degrees. what was the temperature at midnight? a) -7*f b) -17*f c) 17*f

-5-12=-17 so it is b)

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine