After decreasiag by 8% during the first year, the value of an investment then increased by $450 during the second year. which equation shows the relationship between the original investment value (v) and the value (n) after the second year? a. 0.08(450+v)=n b. 0.08v+450=n c. v+0.08v-450=n d. v-0.08v+450=n

Original investment is V

In the first year V decreased by 0.08V to give V - 0.08V

In the second year; V - 0.08V increased by $450 to give V - 0.08V + $450

The value (n) after two years = V - 0.08V + $450

The correct choice is 'D.'

95.03 is the answer. hope this !

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)