Identify any zeros of y=x^2+4x+5. a. there are no zeros. b. (5,,0) c. (-1,,0) d. (0,0)

A there are no real zeros

using the discriminant b² - 4ac  to determine the nature of the zeros

for y = x² + 4x + 5 ( with a = 1, b = 4 and c = 5 )

• If b² - 4ac > 0 there are 2 real and distinct zeros

• If b² - 4ac = 0 there is a real and equal zero

• If b² - 4ac < 0 there are no real zeros

b² - 4ac = 16 - 20 = - 4

Since discriminant < 0 there are no real zeros

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer