Given one factor of the polynomial, factor the polynomial completely. 16. f(x)=x^3-4x^2-7x+10; x-5 17. g(x)=2x^3+3x^2-23x-12; 2x+1

Use synthetic division to solve these problems

5 | 1    -4   -7    10

  |  v    5    5   -10

     1     1    -2    0

This leads to x^2+x-2          

Next we find what adds to 1 and multiplies to -2

The factors of f(x) are 2 and -1, written out as (x+2) and (x-1)

-1/2 | 2     3     -23    -12

      | v     -1       -1      12

        2      2    -24     0

This leads to 2x^2+2x-24

Next, multiply the 2 from the a value (since a is the value with x^2 and c is the value without any x) with -24, which is -48

Now find what adds to 2 and multiplies to -48

The values for this are 8 and -6, but keep in mind, when multiplying the value of a by c, you now have to add the values in place of what you tried adding it to, this time in the problem we found using synthetic division, in this case the 2 in the b value (the middle of the equation, or the value with only one x)

2x^2+8x-6x-24

When group factoring, you'd get 2x(x+4) -6 (x+4)

So, the factors of g(x) are (x+4) and (2x-6)

marco saved more.   he saved $35 more.

step-by-step explanation:

1+2+3+4+5+6+7+8+9+10 = 55

2*10 = 20

55-20 = 35

439400

step-by-step explanation:

130^2 = 16900

16900*26 = 439400