Will give the brainiest to whoever answers first 4.what are the coordinates of the vertex of y = –x2 – 12x – 32? 5.what's the y-intercept of y = –x2 – 12x – 32? 6.find any zeros of y = –x2 – 12x – 32.

Question 1:

For this case we have:

The value of the x coordinate of the vertex is with the equation given by:

Where b = -12 and a = -1

therefore,

To find the coordinate and substitute in the equation:

The coordinates of the vertex are (-6.4)

Question 2:

For this case we have the following equation:

By definition, to find the intercept point with the y axis, we make x = 0 and substitute as shown below:

Thus, the intercept point with the y axis is given by (0, -32)

 the y-intercept is (0, -32)

Question 3:

For this case we have the following equation:

The zeros of the function are given by the cut points with the x axis, so, equaling the equation to zero and clearing x we have:

Rewriting the equation we have:

Factoring has the following:

Thus, the solutions are given by:

Therefore, the zeros of the equation are (-4.0) and (-8.0)

(-4.0) and (-8.0)

abde or 1,2,4, 5 is the answer

step-by-step explanation:

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