Agold mine has two elevators, one for equipment and another for the miners. the equipment elevator descends 4 feet per second. the elevator for the miners descends 15 feet per second. one day, the equipment elevator begins to descend. after 30 seconds, the elevator for the miners begins to descend. what is the position of each elevator relative to the surface after another 14 seconds? at that time, which elevator is deeper?

Let represent the depth of the miner and equipments elevator, respectively. We know that equipment elevator descends with a velocity of feet per second, and the miners one descends with a velocity of feet per second.

If we start counting time () when the equipment elevator begins to descend, after seconds its depth will be

On the other hand, the miner elevator follows the same rule, but we have to use its velocity, and remember that it starts with a delay of thirty seconds:

Now, we have to wait the 30 seconds of delay, and then another 14 seconds. This means that we want to know the positions of both elevators when . Let's plug this value into the two equations:

So, the equipment elevator is 176 feet deep, and the miner elevator is 210 feet deep, and thus this is the deeper one.

your answer is 228

step-by-step explanation:

add the top and bottom bases together, then divide them by 2, then multiply by the height.

step-by-step explanation: