Me! brainlest! given: abcd ∥gram, bk ⊥ad , ab ⊥bd ab=6, ak=3 find: m∠a, bk, and the area of abcdi mean m< a=60 and bk=3 root 3 but idk what the area is.

1) m∠A=60°

2)

3) The area of ABCD is 62.35

Step-by-step explanation:

1) - You can calculate the angle m∠A as following:

- Substitute values and solve for the angle. Let's call the angle m∠A ""

2) Apply the Pythagorean Theorem to find BK:

3) - If you analize the figure, you can see that the triangle ABD and the triangle BCD are the same triangle, both are equal, therefore both have the same area.

- Then, you can calculate the area of ABD and multiply it by 2 to calculate the area of ABCD. The area of a triangle is:

- The area ABD will be the sum of the area of the triangle ABK and the area of the triangle KBD.

- First, you must calculate the angle m∠D using the triangle ABD, which is a right triangle. The sum of the interior angles of a triangle is 180°. You know the angles m∠A (60°) and m∠B (90°), therefore:

m∠D=30°

- Now, you can calculate KD:

- The area of ABCD is:

4x and 6y

im not sure though