Arectangle has a width of 2cm and a perimeter of 25cm. find the length and the area .

2w + 2l = 25

2 * 2 + 2l = 25

Simplfiy.

4 + 2l = 25

Subtract 4 from both sides.

2l = 21

Divide both sides by 2.

l = 10.5

Now that we have the value of l, we can find the area.

A = lw

A = 10.5 * 2

A = 21.

The length is 10.5cm.

The area of the rectangle is 21cm^2

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: