Let f(x)=(x+3)^2and g(x)=f(x)-7. which of the following shows g(x)?

F(x) = (x + 3)²

g(x) = f(x) - 7.

g(x) = (x + 3)² - 7

g(x) = (x + 3)(x + 3) - 7

g(x) = x*x + x*3 +3*x + 3*3 - 7

g(x) = x² + 3x + 3x + 9 - 7

g(x) = x² + 6x + 2

Distance=slopeslope is -2/4which equals-1/2the distance between these two points is -1/2

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