Three consecutive even integers are such that the sum of the seconds and third is 6 more than twice the first. find the integers

Three consecutive even integers are such that the sum of the smallest and 3 times the second is 38 more than twice the third. what are the integers?

1st: 2x-2

2nd: 2x

3rd: 2x+2

Equation:

2x-2 +3(2x)= 2x+2+38

2x-2 + 6x = 2x +40

6x = 42

x = 7

1st: 14-2 = 12

2nd: 14

3rd: 14+2 = 16

show us the graphs dude

step-by-step explanation:

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: