In isosceles triangle the length of the base is twice shorter than the length of a leg. the perimeter of this triangle is 50 cm. find the lengths of all sides.

The length of the base is 10 and the length of each leg is 20.

In order to find this, we can start by making the length of the base x. Now we know that the legs are twice as long, which would make them 2x. Since there are two of them, we can add x + 2x + 2x and set equal to 50 to find the value of x.

x + 2x + 2x = 50

5x = 50

x = 10

Now we can plug this in for our leg length as well to find that.

2x = Leg

2(10) = Leg

20 = leg

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: