In 2000 the total amount of gamma ray bursts was recorded at 6.4 million for a city. in 2005, the same survey was made and the total amount of gamma ray bursts was 7.3 million. if the earth can only withstand 1 billion gamma ray bursts, in what year will this become a problem? (find the year in which the gamma ray bursts is 1 billion.)

Let's assume

It started in 2000

so, t=0 in 2000

we can use formula

we can plug value

In 2005, the same survey was made and the total amount of gamma ray bursts was 7.3 million

so, at t=2005-2000=5

P(t)=7.3 million

we can plug value and then we can solve for r

now, we can plug back

now, we have

P(t)=1 billion =1000 million

so, we can set it and then we can solve for t

approximately

Year is 2000+192

year is 2192................Answer

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

walter needs to make at least 5 more cookies but no more than 40. 5 ≤ x ≤ 40

step-by-step explanation:

20 ≤ x + 15 ≤ 55

subtract 15 from all parts

20-15 ≤ x + 15-15 ≤ 55-15

5 ≤ x ≤ 40

this means how many more cookies he has to make

walter needs to make at least 5 more cookies, but no more than 40 cookies; 5 ≤ x ≤ 40