The science fair project s are set up on tables. there are 99 long tables used. each long table holds 7 projects. the rest of the projects are set up on short tables. each short table can hold 4projects. what is the fewest number of short tables that will be needed for the rest of projects

There are a few missing information that are pertinent to this problem.

Grade:                                                3         4         5
Number of science fair projects: 462    759     891

Total number of projects: 462 + 759 + 891 = 2112

99 long tables * 7 projects = 693 projects

2112 - 693 = 1419 projects

1419 projects ÷ 4 projects/short table = 354.75 tables or 355 short tables needed.

total projects: 2112
projects on long table: 693
projects on short table: 1419

If the diameter is 8 than the radius is 4 because 2r or 2*radius equals the diameter. 4*2=8. 8/2=4.