Which ordered pair (m, n) is a solution to the given system of linear equations? 6m-5n= 14 2m+2n= -10 a) (-4,-1) b) (-31/11,-24/110 c) (-1,-4) d) (11,-16) not b

Option C

Step-by-step explanation:

given two equations

6m-5n= 14   ... i

2m+2n= -10  ...ii

We can solve this by elimination.

For elimination consider the coefficients of m.

They are 6 and 2, with LCD 6

You multiply 2nd equation by 3 to have

6m+6n =-30 ... iii and

6m-5n  = 14  ... i

Subtract i from iii

11n = -44

Divide by 11 to get n

n = -4

Substitute in I equation

6m-5(-4) =14

6m +20 = 14

subtract 20

6m =14-20 =-6

divide by 6

m =-1

Hence answer is m=-1 and n=-4

(-1,-4)

Option C is the answer.

go on the tube you might find some information there

“a term can be a signed number, a variable, or a constant multiplied by a + sign or j sign. in , the terms are 5x , 3y and 8. when a term is made up of a constant multiplied by a variable or variables, that constant is called a coefficient.” i hope this you.