#34. find the value of x for the rectangle. (how did u do it/what did u do)

Hey, CadenClough! For this, it's best to use algebra. We know that rectangles have two of each measure: two lengths and two widths. This means the formula to find the complete perimeter of the rectangle is 2l + 2w = p.

Now let's look at the problem. For length, we have x + 3 and for width we have 2x - 6. First off, fill in the values for length and width in the perimeter equation like this:

Now distribute the 2:

Combine like terms:

Simplify:

Isolate x:

-->

Now plug in the value of x:

= 64/3 - 12 + 32/3 + 6

= 26

So x = or 16/3.

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.

i believe it is 0.1m because the measurement of 30.4m limits how precise you can be

you can only be as precise as the least precise measurement