One number is 6 less than 3 times another number and their sum is 62.find the numbers

y = 6 - 3x

x + y = 62

Since we already know the value of y, we can use substitution to find the value of x.

x + 6 - 3x = 62

Subtract 6 from both sides.

x - 3x = 56

Combine like terms.

-2x = 56

Divide both sides by -2

x = -28

Now that we know the value of x, we can solve for the value of y.

x + y = 62

-28 + y = 62

Add 28 to both sides

y = 90

The value of y is 90, and the value of x is -28 (this is your answer)

To make sure that these values are correct, we can plug them into the original equations.

y = 6 - 3x

x + y = 62

90 = 6 - 3(-28)

90 = 90 √ this is correct

-28 + 90 = 62

62 = 62 √ this is also correct

2

step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0