Me asap . will mark brainliest ! a company commits to reducing its petroleum fuel use by 10% each year from the preceding year. if the company used 20,000 gallons of fuel in the year prior to starting the program, which formula, f(n), represents the fuel used during year n of the program? a. f(n)=20,000- 0.9^n b. f(n)=20,000^0.9n c. f(n)= (20,000*0.9)^n d. f(n)=20,000(0.9)^n

Your answer is D.


Company will reduce the fuel use by 10% each year.
100% - 10% = 90%
So it will use 90% of what it had used previous year.

the company used 20,000 gallons of fuel in the year prior to starting the program.

Next year, it will use = 20000× 90/100 = 20000 × 0.9

in 2nd year, it will use = (20000×0.9) × 0.9 = 20000 × 0.9^2

in 3rd year, it will use = (20000× 0.9^2) × 0.9 = 20000 × 0.9^3

See the pattern.

Fuel to be used in nth year = 20000 × 0.9^n

So f(n) = 20000× 0.9^n = 20000(0.9)^n

Answer: c. x y2 04 66 16