Acar is moving with a velocity (3.0 m/s) x̂ + (1.0 m/s) ŷ and 3.0 seconds later its velocity is (6.0 m/s) x̂ - (3.0 m/s) ŷ. what is the direction of the average acceleration of the car?

Here we know that the initial velocity of the car is given by:

And the final velocity of the car is given by:

It took 3 seconds to attain the final velocity, so we have

Therefore, the acceleration can be obtained by:

Plugging the values of the initial, final velocity and the time, we get:

So the acceleration of the car is given by:

Now we need to find the direction of the average acceleration of the car:

Here, x and y are the coefficients of the 'x' and 'y' components of the vector:

Therefore, the direction of the average acceleration of the car is .

the answer is 31.27mph