Solve the system. if there's no unique solution, label the system as either dependent or inconsistent. 2x + y + 3z = 12 x – y + 4z = 5 –4x + 4y – 4z = –20 a. dependent system (infinite number of solutions) b. inconsistent system (no solution) c. (4, 1, 2) d. (1, 4, 2)

The solution of the equations are

So all the options are wrong.

Step-by-step explanation:

We have

    2x + y + 3z = 12 -------------------eqn 1

    x – y + 4z = 5 -------------------eqn 2

    –4x + 4y – 4z = –20 -------------------eqn 3

eqn 2 x 2

   2x – 2y + 8z = 10 -------------------eqn 4

eqn 4 - eqn 1

   2x – 2y + 8z - (2x + y + 3z) = 10 - 12

   -3y +5z = -2 -------------------eqn 5

eqn 1 x 2

    4x + 2y + 6z = 24 -------------------eqn 6

eqn 3 + eqn 6

      –4x + 4y – 4z + 4x + 2y + 6z = -20 + 24

       6y + 2 z = 4 -------------------eqn 7

eqn 5 x 2

      -6y +10z = -4 -------------------eqn 8

eqn 7 + eqn 8

      12 z = 0

       z = 0

Substituting in eqn 7

        6y + 0 = 4

Substituting in eqn 2

So the solution of the equations are

So all the options are wrong.

answer: the 4 kilogram bag

step-by-step explanation: this is because if you divide the number of kilograms into the total it will tell you how much each individual kilogram would be worth. 2 kilos is 7 and change 3 would be around 6 ish and the 4 kilo would be 4.6 and change and the 5 kilos would be like 4.88