Solve the problem. 3⋅(6^12/6^10) a) 26 b)39 c)92 d)108

Hey there!!

To solve this, we will need to use the division property of exponents, which is :

mᵃ / mᵇ = mᵃ⁻ᵇ

In the question,

m = 6 ; a = 12 and b = 10

6¹² / 6¹⁰ = 6¹²⁻¹⁰ = 6² = 36

3 ( 36 ) = 108

Hope my answer helps!!

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

16.80 times .20= 3.36

step-by-step explanation: