The equation 2x^2+12x=4 is written in the form of 2(x-p)^2+q=0. what is the value of q?

1) Factor out the coefficient 2:  2x^2+12x=4 => 2(x^2 + 6x) = 4

2) Complete the square of x^2 + 6x:  x^2 + 6x + 9 - 9.  Then:

                                                    2(x^2 + 6x + 9 - 9) = 4

3) Rewrite the square as the square of a binomial:

                                                    2( [x+3]^2 - 9) = 4, or

                                                     2([x+3]^2)       = 22, or

                                                     2( [x+3]^2 ) - 22 = 0

The value of q is -22.

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