Mark bikes 4/10 of a mile in 1/5 of an hour. find marks average speed in miles per hour. i’m

Mark bikes 4/10 of a mile in 1/5 of an hour.

That is 4/10miles in 1/5hours

Average speed = Distance ÷ time

= 4/10 ÷ 1/5 = 4/10 ×5/1 = 2 miles/hour

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

there is no points to select.

step-by-step explanation: