Twice the sum of 2 consecutive integers equals 106. determine the value of each integer

Hey there!!

Given word equation :

Let's take the first equation as ' x '

Then, the second number would be ' x + 1 '

Twice the sum of these = 106

Equation :

... 2 ( x + x + 1 ) = 106

... 2 ( 2x + 1 ) = 106

... 4x + 2 = 106

Subtract 2 on both sides

... 4x = 104

Divide by 4 on both sides

... x = 26

The first number= 26 and the second number = 27

The numbers are 26 and 27.

Hope my answer helps!

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363