Find the coordinates of the points of intersection of the graph of y=13−x with the axes and compute the area of the right triangle formed by this line and coordinate axes.

The point at which two lines meet is referred to as the point of intersection.

The linear equation is given as:

Intersection with the y-axis

Set ,

This means that: intersects with the y-axis at:

Intersection with the x-axis

Set ,

This means that: intersects with the x-axis at:

The area of the right-angled triangle

The area is calculated as:

In this case,

So, we have:

This gives:

Hence, the area of the triangle is 84.5 square units

See attachment for the graph of  

Read more about graphs at:

link

The x- and y-intercepts are both 13, so the area is ...

... A = (1/2)bh = (1/2)·13·13 = 169/2 = 84.5 . . . square units

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Solve for x when y=0 to find the x-intercept:

... 0 = 13 - x

... x = 13 . . . . . add x

Solve for y when x=0 to find the y-intercept:

... y = 13 - 0

... y = 13 . . . . . additive identity property of 0

the answer i think is a)

step-by-step explanation:

for b its (t) and c its (d)

step-by-step explanation: