Find values of a and b that make the statement |a+b|= |a|+|b| false.

The values that make this statement falser are any in which a and b do not have the same sign.

For instance, if a was equal to 3 and b was equal to -3 than see the results.

|a+b|=

|3+-3|=

|0|= 0

Then see the next equation with the same selections

|a|+|b|

|3|+|-3|

3 + 3 = 6

And this would be true no matter which is the negative, as long as there is one negative and one positive.

16.9 times 2.85

step-by-step explanation:

(-5,-28)

i graphed to on desmos.