Mathematics, 09.07.2019 02:00 korban23
Write the expression as a complex number in standard form- -2i(1+i)(2+3i)
Answers: 1
\\\\=(-2i-2i^2)(2+3i)\qquad i=\sqrt{-1}\to i^2=-1\\\\=(-2i+2)(2+3i)\qquad\text{use distributive property}\\\\=(-2i)(2)+(-2i)(3i)+(2)(2)+(2)(3i)\\\\=-4i-6i^2+4+6i\qquad i=\sqrt{-1}\to i^2=-1\\\\=-4i+6+4+6i\qquad\text{use commutative and associative property}\\\\=(6+4)+(-4i+6i)\\\\=\boxed{10+2i}](/tpl/images/0067/7501/39370.png)
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Write the expression as a complex number in standard form- -2i(1+i)(2+3i)...
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