An earthworm of length 15cm is crawling along at 2cm/s. an ant overtakes the worm in 5 seconds. how fast is the ant walking?

Assume we have a number line, where the tail of the worm is at x=0. This means that the head of the worm is at x=15.

Also, we know that the coordinate of the head of the worm follows this equation:

Where is the time in seconds. In fact, we know that the worm gains 2 centimeters per second.

Now, assume that the ant also starts at x=0, and walks with a certain rate of centimeters per second. This means that the equation for the position of the ant is

Now, we know that after 5 seconds the ant is in the same position as the head of the worm, which means

We know the equation for both expressions, so let's subtitute them in:

So, the ant walks at a rate of 5cm per second.

answer: #1 ads up by 8 and i don't know #2