Mathematics, 09.07.2019 03:30 Chipper4085
Explain why the cube root of 64 is rational and the cube root of 1 2 is not.
Answers: 1
![\sqrt[3]{64}=4](/tpl/images/0067/9617/51f90.png)
so it's obvious, I guess :)![\sqrt[3]{12}](/tpl/images/0067/9617/81b19.png)
is not rational number.
where 
and 
.![\sqrt[3]{12}=\dfrac{a}{b}\\\\12=\dfrac{a^3}{b^3}\\\\a^3=12b^3](/tpl/images/0067/9617/0a357.png)
is an even number, so 
must also be an even number, and therefore also 
must be an even number. So, we can say that 
, where 
.
is an even number, then also 
must be an even number. 3 is odd, so for 
must be an even number, and therefore 
is an even number.
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Explain why the cube root of 64 is rational and the cube root of 1 2 is not....
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