Acarpool contains three kindergartners and five first-graders. if two children are ill, find the probability that at least one of them is a kindergartner.

Solution: We are given that there are three kindergartners and five first-graders.

We have to find the probability that at least one of them is a kindergartner.

We know that:

P(at least one kindergartner) = 1 - P(no kindergartner) = 1 - P(all first-graders)

Now, P(all first-graders)

Therefore, P(at least one kindergartner)

sin3a=12/15

step-by-step explanation:

since one side was multiplied by 3 the other side must also be multiplied by 3.

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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