Mrs. mcalister wrote the equation 10t-4t+3t=8 on the board and asked students to write an equivalent equation. the table below shows the responses from four students. student responses name 1.michele 2.piotr 3.ronnie 4.tanisha equation 1.3t=8 2.6t=8 3.-1t=8 4.9t=8 which student wrote an equation that is equivalent to mrs. mcalister’s? michele piotr ronnie tanisha

Tanisha wrote an equation that is same as Mrs. McAlister's equation.

9t = 8

Step-by-step explanation:

Mrs. McAlister wrote an equation on the board is:

10t-4t+3t=8

Now we simplify this

In order to simplify the left side, we combine like terms.

Here 10t, -4t, & 3t are like terms

So, 10t - 4t + 3t is equivalent to 9t

Thus,

9t = 8

This equation is written by the Tanisha.

That's the final answer.

I hope it helps you.

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

answerthe vertex form

step-by-step explanation: