Answer the questions below by drawing on the coordinate plane.

Coordinates of the given triangle:

P (1,-1)

Q (3,-2)

R (3,-4)

A) we need to apply transformation "180 degree about the origin".

If we have (x,y) coordinates of the given triangle.

On rotating 180 degrees about origin, we get (-x,-y) coordinates of the transformed triangle.

Therefore, we can apply rule (x,y) --> (-x,-y) for a part.

By applying above rule, we get new coordinates of the transformed triangle:

P (1,-1) ---> P'(-1,1)

Q (3,-2) ---> Q'(-3,2)

R (3,-4) ---> R'(-3,4)

Now, we can plot those coordinates on the graph.

B) we need to reflect Triangle P'Q'R' across x-axis.

If we have (h,k) coordinates of the P'Q'R' triangle.

On reflecting Triangle P'Q'R' across x-axis, only y coordinates would get multiply by -1 and we get (h,-k) coordinates of the reflected triangle.

Therefore, we can apply rule (h,k) --> (h,-y) for b part.

By applying above rule, we get new coordinates of the transformed triangle:

P'(-1,1) ---> P"(-1,-1)

Q'(-3,2) ---> Q"(-3,-2)

R'(-3,4) ---> R"(-3,-4)

Now, we can plot those coordinates on the graph.

do you have a picture of the table

answer:   (s+1)(s+4)

step-by-step explanation:

factor s2+5s+4

s2+5s+4

=(s+1)(s+4)