The sum of two integers is 74. the larger is 26 more than twice the smaller. find the two integers.

n - the larger of two i ntegers

m - the smaller of two integers

n + m = 74 → n = 74 - m

n = 2m + 26

Therefore we have:

2m + 26 = 74 - m    |subtract 26 from both sides

2m = 48 - m    |add m to both sides

3m = 48     |divide both sides by 3

m = 16

n = 74 - 16 = 58

16 and 58.

were is the equation

it would take 7/10 of an hour too fill the pool.

step-by-step explanation: