Qis in the interior of angle ros s in the interior of angle qop. p is in the interior of angle sor. s is in the interior of angle rot and the measure of angle rot is 160° the measure of angle sot is 100° and the measure of angle roq to equals the measure of angle qos equals the measure of angle pot

∠ROT=160°

∠SOT=100°

Now ∠SOR= ∠ROT - ∠SOT

∠ SOR = 160°-100°

∠ SOR =60°

It is given that measure of angle ROQ to equals the measure of angle QOS equals the measure of angle POT.

∠SOQ + ∠QOR = 60°

But ∠SOQ = ∠QOR

2∠SOQ=60°

∠SOQ=60°÷2

∠SOQ =30°

Also ∠POT=∠SOQ=∠ROQ=30°

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2