Find the measures of supplementary angles 1 and 2, if: m∠1 is less than m∠2 by 40° include your explanation

Since they are supplementary angles, both of them will add up to 180°

m∠1+m∠2=180

m∠1 is less than m∠2 by 40°

m∠1+40=m∠2

Substitute m∠1+40 for m∠2

m∠1+m∠1+40=180

2(m∠1)+40=180

          -40    -40

2(m∠1)=140

2(m∠1)/2=140/2

m∠1=70°

70°+m∠2=180°

-70            -70

m∠2=110°

m∠1=70°    

              m∠2=110°

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

i'm sorry i don't know

step-by-step explanation: