Candy selling at $6.00 per pound will be mixed with candy selling at $9.00 per pound. how many pounds of the more expensive candy are needed to produce a 15-pound mixture that sells for $7.00 per pound? a. 5 b. 6 c. 9 d. 10

x+y=15 the total of 15 pounds

(6x+9y)/15=7 the average of each pound out of 15 that is valued $7

(6x+9*(15-x))/15=7

(6x+135-9x)/15=7

(135-3x)/15=7

135-3x=7*15

135-3x=105

-3x=-30

x=10

deduce that y=15-10=5

so basically, you can conclude that 10 of the 1st candies are valued at 60$ and 5 pound of the second will be valued at at $45 which adds up to $105

and 105/15=7 which shows us that we were right and overall 15 pounds has and average pound value of $7

hope this : )

105/15=7 which means that overall 15   pounds do have an average per-pound value of 7

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0