Agroup of winning ticket holders share equally 90,000,000 lottery. before the money is divided, three more winning ticket holders are declared. as a result, each persons share is reduced to 5,000,000. how many people were in the original group of winners

Let's assume

people were in the original group of winners as x

A group of winning ticket holders share equally 90,000,000 lottery

Before the money is divided, three more winning ticket holders are declared

so, total number of winning tickes =x+3

each persons share is reduced to 5,000,000

so, total money =5,000,000*(x+3)

and this must be equal to total money

now, we can solve for x

and we get

Subtrac both sides by 3

so,

number of people were in the original group of winners is 15 ...........Answer

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13