The first order was for 13 bushes and 4 trees, and had a total of $432. the second order was for 6 bushes and 2 trees, and had a total of $232. what was the cost of one bush?

DISCLAIMER: One of the solutions of this system is negative, which seems strange. Make sure there are non typos in the question!

Let b be the price of a bush and t the price of a tree. The two orders translate to the following linear system:

Multiply the second equation by 2:

Subtract the second equation from the first:

Substitute this value in the first equation (for example) to compute the value of t:

well what did you do it matters what you did : )

step-by-step explanation:

total of apples - take away four

6-4 = 2

answer is 2 apples